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-3t^2+73t+50=0
a = -3; b = 73; c = +50;
Δ = b2-4ac
Δ = 732-4·(-3)·50
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5929}=77$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(73)-77}{2*-3}=\frac{-150}{-6} =+25 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(73)+77}{2*-3}=\frac{4}{-6} =-2/3 $
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